2(3x-1)²-32=0 27(1-4x)³=125求X的值
问题描述:
2(3x-1)²-32=0 27(1-4x)³=125
求X的值
答
2(3x-1)^2-32=0 (3x-1)^2=16 3x-1=4或-4 3x=5或-3 x=5/3或-1 27(1-4x)^3=125 ^3=125 3(1-4x)=5 1-4x=5/3 -4x=2/3 x=-1/6
答
2(3x-1)²-32=0 2(3x-1)²=32(3x-1)²=163x-1=±43x=5或者-33x=5 x=5/33x=-3 x=-127(1-4x)³=125(1-4x)³=125/271-4x=5/34x=1-5/34x=-2/3x=-1/6