x/x-3减x+6/x^2-3x加3/x,其中x=3/2
问题描述：
x/x-3减x+6/x^2-3x加3/x,其中x=3/2
答
先将式子进行化简：x/x-3 - x+6/x²-3x + 3/x
=x²/x(x-3) - x+6/ x(x-3) + 3(x-3)/x(x-3)
=x²-（x-6)+3（x-3）/ x(x-3)
=x²+2x-15 / x(3-x)
=(x-3)(x+5)/x(x-3)
=(x+5)/x
=1 + 5/x
将x=3/2代入，原式=13/3
答
x/x-3减x+6/x^2-3x加3/x
=[x*x-(x+6)+3(x-3)]/x(x-3)
=(x^2-x-6+3x-9)/x(x-3)
=(x^2+2x-15)/x(x-3)
=(x+5)(x-3)/x(x-3)
=(x+5)/x
所以原式
=13/3