log3^2log5^7/log9^1/7log125^82.log2^3=1-a/a,则log3^12=

分类: 作业答案 • 2021-12-19 16:46:27

问题描述：

log3^2*log5^7/log9^1/7*log125^8
2.log2^3=1-a/a,则log3^12=

答

log9^1/7*log125^8=（1/2）log3^1/7*（1/3*3）log5^2=（1/2）log3^1/7*log5^2
∴log3^2*log5^7/ log9^1/7*log125^8=49/24

答

2log3*7log5/(2/7)log3*24log5=49/24

log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=