2x(x-1)+2=x(x+1)

问题描述:

2x(x-1)+2=x(x+1)

l两边打开括号,乘进去
2x^2-2x+2=x^2+x
x^2-3x+2=0
(x-1) (x-2)=0
x=1,x=2

2x^2-2x+2=x^2+x
x^2-3x+2=0
(x-2)(x-1)=0
x=2或X=1

2x^2-2x+2=x^2+x
x^2-3x+2=0
(x-2)(x-1)=0
x=2,x=1