已知4X^2-3X+1=a(x-1)+b(x-1)+c对任意X值成立,求4a+2b+c的值谢谢了,

问题描述:

已知4X^2-3X+1=a(x-1)+b(x-1)+c对任意X值成立,求4a+2b+c的值谢谢了,

左边:4x^2-3x+1 右边:ax^2 - 2ax + a + bx - b + c =ax^2 - (2a - b)x + (2 - b + c) 左右两边同样的次数系数应该一样,也就有 4 = a -3 = -(2a - b) 1 = a - b + c a = 4 b = 5 c = 2 4a+2b+2 = 28...