已知x/y=2/3,则2x-y/x+2y的值是多少?
问题描述:
已知x/y=2/3,则2x-y/x+2y的值是多少?
答
(2x-y)/(x+2y)
=(2x/y-1)/(x/y+2)
=(2X2/3-1)/(2/3+2)
=1/3÷8/3=1/8
答
2x-y/x+2y是(2x-y)/(x+2y)吧
(2x-y)/(x+2y)=(2x/y-1)/(x/y+2)=(2X2/3-1)/(2/3+2)=1/3÷8/3=1/8