已知α,β在(0,π/2)区间,且3(sinα)^2+2(sinβ)^2=13sin2α-2(sinβ)^2=0求证:α+2β=π/2,并求tan2α{注明:3(sinα)^2 是指3乘以sinα的平方}

问题描述:

已知α,β在(0,π/2)区间,且3(sinα)^2+2(sinβ)^2=1
3sin2α-2(sinβ)^2=0
求证:α+2β=π/2,并求tan2α
{注明:3(sinα)^2 是指3乘以sinα的平方}

tan2α=1
α+2β=90°