已知x是一元二次方程x²+3x-1=0的实数根,求代数值3x²-6x分之x-3 ÷ [x+2- (x-2分之5)]
问题描述：
已知x是一元二次方程x²+3x-1=0的实数根,求代数值3x²-6x分之x-3 ÷ [x+2- (x-2分之5)]
答
1/3 原式= 1/3x²+9x x²+3x-1=0 x²+3x=1 3x²+9x =3
答
已知x是一元二次方程x²+3x-1=0的实数根
则x²+3x=1
(x-3)/(3x²-6x)÷[x+2- 5/(x-2)]
=(x-3)/[3x(x-2)]÷[(x²-4-5)/(x-2)]
=[(x-3)/3x(x-2)]*(x-2)/[(x+3)(x-3)]
=1/[3x(x+3)]
=1/[3(x²+3x)
=1/3