初二下数学分式计算3y/2x+2y+2xy/x²+xy

问题描述:

初二下数学分式计算3y/2x+2y+2xy/x²+xy

3y/(2x+2y) +2xy/x²+xy
=3y/2(x+y)+2xy/x(x+y)
=3xy+4xy/2x(x+y)
=7xy/x+y

3y/2(x+y)+2y/(x+y)=7y/2(x+y)