1+3+5+7+.+(2n-1)
问题描述:
1+3+5+7+.+(2n-1)
答
1+3+5+7+。。。。+(2n-1)
=(1+2n-1)*(2n-1+1)÷2÷2
=4n²/4
=n²
答
1+3+5+7+...+(2n-1) (等差数列)
1+3+5+7+...+(2n-1)
=(2n-1)*(1+2n-1)/2
=(2n-1)*n
=2n^2-n