(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)(x1x2-1)/x1x2 这一步怎么推出来的,(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)(x1x2-1)/x1x2 这一步怎么推出来的,

分类: 作业答案 • 2023-01-24 11:52:17

问题描述：

(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)(x1x2-1)/x1x2 这一步怎么推出来的,
(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)(x1x2-1)/x1x2 这一步怎么推出来的,

答

(x1-x2)+(x2-x1)/(x1x2)
=(X1-X2)*[1-1/(X1*X2)]
=(X1-X2)*[(X1*X2-1)/X1*X2]

答

(x1-x2)+(x2-x1)/(x1x2)
=[(x1-x2)+(x2-x1)]/(x1x2)
=[(x1x2)(x1-x2)-(x1-x2)]/(x1x2)
=(x1-x2)(x1x2-1)/x1x2

答

通分
分子=x1x2(x1-x2)-(x1-x2)
=(x1-x2)(x1x2-1)

答

(x1-x2)+(x2-x1)/(x1x2)
=x1x2(x1-x2)/x1x2+(x2-x1)/(x1x2)
=[x1x2(x1-x2)-(x1-x2)]/x1x2
=(x1-x2)(x1x2-1)/x1x2