已知(a^2+1)(b^2+1)-6ab+3=0,求2a^2b+2ab^2D的值.

问题描述:

已知(a^2+1)(b^2+1)-6ab+3=0,求2a^2b+2ab^2D的值.

已知(a^2+1)(b^2+1)-6ab+3=0,a²b²+a²+b²+1-6ab+3=0;a²b²-4ab+4+a²+b²-2ab=0;(ab-2)²+(a-b)²=0;ab=2;a-b=0;a=b;a=b=±√2;求2a^2b+2ab^2=2ab(a+b)=2×2×(±2√2)...