∫上限π/2下限0 sin^3 xdx
问题描述：
∫上限π/2下限0 sin^3 xdx
答
∫(0到π/2) sin³x dx
= ∫(0到π/2) sin²x d(-cosx)
= ∫(0到π/2) (cos²x-1) d(cosx)
= (1/3*cos³x-cosx)[0到π/2]
= (0-0)-(1/3-1)
= 2/3