(4x+3)(2x-3)-6x(3/2x+1)那里是2分之3来的,
问题描述:
(4x+3)(2x-3)-6x(3/2x+1)那里是2分之3来的,
答
(4x+3)(2x-3)-6x(2x/3+1)=(4x+3)(2x-3)-2x(2x+3)==8x²+6x-12x-9-9x²-6x=-x²-12x-9
(4x+3)(2x-3)-6x(3/2x+1)那里是2分之3来的,
(4x+3)(2x-3)-6x(2x/3+1)=(4x+3)(2x-3)-2x(2x+3)==8x²+6x-12x-9-9x²-6x=-x²-12x-9