解方程:ax2-(a+1)x+1=0(a为常数且a不等于0)
问题描述:
解方程:ax2-(a+1)x+1=0(a为常数且a不等于0)
答
ax²-ax-x+1=0
ax(x-1)-(x-1)=0
(ax-1)(x-1)=0
x=1/a,x=1