解不等式:(x^2-3x-18)/(6x^2-5x+1)
问题描述:
解不等式:(x^2-3x-18)/(6x^2-5x+1)
答
(x² - 3x - 18) / (6x² - 5x + 1) [(x + 3)(x - 6)] / [(2x - 1)(3x - 1)] -3
解不等式:(x^2-3x-18)/(6x^2-5x+1)
(x² - 3x - 18) / (6x² - 5x + 1) [(x + 3)(x - 6)] / [(2x - 1)(3x - 1)] -3