12%x+10%(18-x)=20-18

问题描述:

12%x+10%(18-x)=20-18

12%x+10%(18-x)=20-18
等式两边等效于,
0.12x+0.1×(18-x)=2
化简,
0.12x+1.8-0.1x=2
移项,
0.12x-0.1x=2-1.8
化简,
0.02x=0.2
解得,
x=0.2÷0.02=10