当x=根号2004-1时,求(x+1)²-6的值

问题描述:

当x=根号2004-1时,求(x+1)²-6的值

(x+1)²-6=x2+2x+1-6

= x2+2x-5

=(√2004-1)2+2×(√2004-1)-5

=2004-2√2004 +1 +2√2004-2-5

=2004 -6

=1998