当x=根号2004-1时,求(x+1)²-6的值
问题描述:
当x=根号2004-1时,求(x+1)²-6的值
答
(x+1)²-6=x2+2x+1-6
= x2+2x-5
=(√2004-1)2+2×(√2004-1)-5
=2004-2√2004 +1 +2√2004-2-5
=2004 -6
=1998
当x=根号2004-1时,求(x+1)²-6的值
(x+1)²-6=x2+2x+1-6
= x2+2x-5
=(√2004-1)2+2×(√2004-1)-5
=2004-2√2004 +1 +2√2004-2-5
=2004 -6
=1998