因式分解：x3-y3-x2y+xy2
问题描述：
因式分解：x3-y3-x2y+xy2
答
x3-y3-x2y+xy2 =(x-y)(x2+xy+y2)-xy(x-y)=(x-y)(x2+xy+y2-xy)=(x-y)(x2+y2)
因式分解：x3-y3-x2y+xy2
x3-y3-x2y+xy2 =(x-y)(x2+xy+y2)-xy(x-y)=(x-y)(x2+xy+y2-xy)=(x-y)(x2+y2)