已知3x²-7x+2=0有两根为x1x2,则x1x2²+x1²x2=?
问题描述:
已知3x²-7x+2=0有两根为x1x2,则x1x2²+x1²x2=?
答
根据题意得
x1+x2=7/3
x1x2=2/3
于是
x1x2²+x1²x2
=x1x2(x1+x2)
=2/3*7/3
=14/9