若X>0,y>0,且x-根号下xy-2y=0,求(2x-根号下xy)/y+2根号下xy的值
问题描述：
若X>0,y>0,且x-根号下xy-2y=0,求(2x-根号下xy)/y+2根号下xy的值
答
题目不很清楚哈,我理解是：已知：x-(xy)^0.5-2y=0;求：（2x-(xy)^0.5)/(y+2*(xy)^0.5);由已知：（x/y)-(x/y)^0.5-2=0; [(X/y)^0.5-2][(x/y)^0.5+1]=0; (x/y)^0.5=2; 求等价于[2(x/y)-(x/y)^0.5]/[1+2*(x/y)^0.5]=6/5...