(-3/2xy)·(2/3x²y-4xy²+4/3y)=

问题描述:

(-3/2xy)·(2/3x²y-4xy²+4/3y)=

原式=(-3/2xy)·2/3x²y-(-3/2xy)·4xy²+(-3/2xy)·4/3y
=-x³y²+6x²y³-2xy²(x-1)(x+1)(x²+1)=哦
采纳我,重新问为什么 这是要花钱的先采纳就行