用配方法解方程3x^2-6x+1=0
问题描述:
用配方法解方程3x^2-6x+1=0
则方程可变形为:
A(x-3)^2=1/3
B 3(x-1)^2=1/3
C (3x-1)^2=1
D (x-1)^2=2/3
请写出过程,谢谢
答
3x^2-6x+1=0
3(x^2-2x)+1=0
3(x^2-2x+1)+1-3=0
3(x-1)^2=2
(x-1)^2=2/3
选D