先化简再求值x+1/x2+1÷(x+1)²-x-3/x+1 其中x=根3+1
问题描述:
先化简再求值x+1/x2+1÷(x+1)²-x-3/x+1 其中x=根3+1
答
=x+1/x2+1*x+1/(x+1)²-x-3 (除以一个数等于乘以这个数的倒数)x2这个是X方吧=(X+1)^2/(X^2+1)(X^2+2X+1-X-3)=(X+1)^2/(X^2+1)(X+2)(X-1)x=根3+1 代入(√3+1)^2/(√3^2+1)(√3+2)(√3-1)=(√3+1)^2/(3+1)(3+√3...