已知x2+y2-2x-4y+5=0,则1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+…+1/(x+2010)(y+2010)的值等于_.
问题描述:
已知x2+y2-2x-4y+5=0,则
+1 xy
+1 (x+1)(y+1)
+…+1 (x+2)(y+2)
的值等于______. 1 (x+2010)(y+2010)
答
∵x2+y2-2x-4y+5=0,
∴x2-2x+1+y2-4y+4=0,
∴(x-1)2+(y-2)2=0,
∴x=1,y=2,
∴原式=
+1 1×2
+…+1 2×3
=1-1 2011×2012
+1 2
-1 2
+…+1 3
-1 2011
=1-1 2012
=1 2012
.2011 2012
故答案是
.2011 2012