y=sin^2x周期怎么算?
问题描述:
y=sin^2x周期怎么算?
答
y=sin^2x
=(1-cos2x)/2
所以T=2π/2=π
y=sin^2x周期怎么算?
y=sin^2x
=(1-cos2x)/2
所以T=2π/2=π