f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域

问题描述:

f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域

x∈[0,π/2]
2x+π/6∈[π/6,7π/6]
当2x+π/6=π/2,f(x)有最大值2
当2x+π/6=7π/6,f(x)有最小值-1
所以值域为[-1,2]