已知x²-4x-1=0求代数式(2x-3)²-(x+y)(x-y)-y²的值
问题描述:
已知x²-4x-1=0求代数式(2x-3)²-(x+y)(x-y)-y²的值
(2)已知9x²+kxy+4y²是完全平方式,求k
答
(2x-3)²-(x+y)(x-y)-y²
=4x²-12x+9-x²+y²-y²
=3x²-12x+9
=3x²-12x-3+12
=3(x²-4x-1)+12
=12
2、k²-4×9×4=0
k²=144
∴k=12或k=-12