抛物线y^2=8x上到焦点的距离为6的点的坐标
问题描述：
抛物线y^2=8x上到焦点的距离为6的点的坐标
写以下过程,谢谢,赶用!
答
y^2=8x,则p=4.焦点坐标是:(2,0)设点是:(m^2/8,m)(m^2/8-2)^2+m^2=36m^4/64+4-m^2/2+m^2-36=0m^4/64+m^2/2-32=0m^4+32m^2-32*64=0(m^2-32)(m^2+64)=0m^2=32m=(+/-)4根号2即点坐标是:(4,4根号2)或(4,-4根号2)...