(1).2x^2-3x+1=0 (2).x^2-2倍根号3x+3=0 (3).3x^2-1=4x (4).2倍根号3x-根号2（x^2+1)=0用公式法怎么解

1). 2x^2-3x+1=0 (2). x^2-2√3x+3=0 (3). 3x^2-1=4x (4). 2√3x-√2（x^2+1)=0用公式法怎么解
建议用十字相乘法来做
1). 2x^2-3x+1=0
1 -1
2 -1
(x-1)(2x-1)=0
x=1,x=1/2
x^2-2√3x+3=0
x^2-2*1*√3+(√3)^2=0
(x-√3)^2=0
x=√3
3x^2-1-4x =0
x=-(-4)+ - √[16-4*3*(-1)]/2*3
x=(4+ - √28)/6
2√3x-√2（x^2+1)=0
-√2 x^2+2√3x-1=0
√2 x^2-2√3x+1=0
x=[2√3+ -√12-4*√2*1]/2*√2

2x^2-3x+1=0(2x-1)(x-1)=0x=1/2或x=1x^2-2√3x+3=0x^2-2√3x+(√3)^2=0(x-√3)^2=0x=√33x^2-1=4x3x^2-4x-1=0x^2-4x/3-1/3=0x^2-4x/3+4/9-4/9-1/3=0=0(x-2/3)^2-7/9=0(x-2/3-√7/3)(x-2/3+√7/3)=0x=2/3+√7/3或x=2/...