8x的六次方减7x的三次方减一.
问题描述:
8x的六次方减7x的三次方减一.
答
8x^6+7x^3-1
=(8x^3+1)(x^3-1)
=(2x+1)(4x^2-2x+1)(x-1)(x^2+x+1)原式=(8x³+1)(x³-1)=(2x+1)(4x²-2x+1)(x-1)(x²+x+1)第二个