(5/2)的2009次方乘以(-2/5)的2010次方得多少?

问题描述:

(5/2)的2009次方乘以(-2/5)的2010次方得多少?

(5/2)的2009次方×(-2/5)的2010次方
= (5/2)的2009次方×(-2/5)的2009次方×(-2/5)
= [5/2×(-2/5]的2009次方×(-2/5)
= (-1)的2009次方×(-2/5)
= (-1)×(-2/5)
= 2/5