计算4x^2-[2x-(x^2-2x+3)-2(x^2-3x)]
问题描述:
计算4x^2-[2x-(x^2-2x+3)-2(x^2-3x)]
要过程!
详细一点!
答
原式=4x^2+3x^2-10x^2+3=(7x-3)(x-1)你有跳步,好象答案不对啊……答案绝对对原式=4x^2-(2x-x^2+2x-3-2x^2+6x)=4x^2+3x^2-10x^2+3=(7x-3)(x-1)