根号2-1分之(根号2+1)(3-2倍的根号2)
问题描述：
根号2-1分之(根号2+1)(3-2倍的根号2)
答
根号2-1分之(根号2+1)(3-2倍的根号2)
＝(√2+1)(3-2√2)÷﹙√2-1﹚
=(3﹢2√2)(3﹣2√2)
=9﹣8
=1
答
原式=（√2+1）^2(3-2√2)=(3+2√2)(3-2√2)=3^2-(2√2)^2=9-8=1