(a+1)(a2+1)(a4+1)(a6+1)(a8+1)+1=
问题描述：
(a+1)(a2+1)(a4+1)(a6+1)(a8+1)+1=
答
(a+1)(a2+1)(a4+1)(a6+1)(a8+1)+1=[(a-1)(a+1)(a2+1)(a4+1)(a6+1)(a8+1)]/(a-1)+1=[(a2-1)(a2+1)(a4+1)(a6+1)(a8+1)]/(a-1)+1=[(a4-1)(a4+1)(a6+1)(a8+1)]/(a-1)+1=(a8-1))(a8+1))(a6+1)]/(a-1)+1==[(a16-1)(a6+1)]/...