已知|x+y+2|+x²y²-2xy+1=0,求x²y+xy²的值快
问题描述：
已知|x+y+2|+x²y²-2xy+1=0,求x²y+xy²的值
快
答
|x+y+2|+(xy-1)^2=0
x+y+2=0,xy-1=0
x+y=-2,xy=1
x^2y+xy^2
=xy(x+y)
=1*(-2)=-2.