已知cos (π/6 -α)=√3/3 ,求cos (5π/6 + α)-sin²(α -π/6)的值

问题描述:

已知cos (π/6 -α)=√3/3 ,求cos (5π/6 + α)-sin²(α -π/6)的值

cos (5π/6 + α)-sin²(α -π/6)=cos(π-(π/6-α))-1+cos²(α-π/6)=-cos(π/6-α)-1+cos²(π/6-α)=-√3/3-1+(√3/3)² 其中cos (π/6 -α)=√3/3=-√3/3-1+1/3=-(2+√3)/3...