隐函数y=x ln y对x求导,谢谢!
问题描述:
隐函数y=x ln y对x求导,谢谢!
答
y=x ln y
y′= ln y+x*(1/y)*y′
[1-(x/y)]y′=lny
y′=lny/[1-(x/y)]
=ylny/(y-x)