[(5x+2y)(3x+2y)+(x+2y)(x-2y)]除以4x

问题描述:

[(5x+2y)(3x+2y)+(x+2y)(x-2y)]除以4x

[(5x+2y)(3x+2y)+(x+2y)(x-2y)]除以4x
=(15x²+6xy+10xy+4y²+x²-4y²)÷4x
=(16x²+16xy)÷4x
=4x+4y

原式=(15x²+16xy+4y²+x²-4y²)/4x
= (16x²+16xy)/4x
=4x+4y
此题是利用多项式的乘法及平方差公式进行计算的,希望你能看得懂,祝学习愉快!