因式分解：x^(3x+2y)^2-y^2(2x+3y),
问题描述：
因式分解：x^(3x+2y)^2-y^2(2x+3y),
题目是这个：x^2(3x+2y)^2-y^2(2x+3y)^2，不小心搞错了
答
x^2(3x+2y)^2-y^2(2x+3y)^2=x^2(9x^2+12xy+4y^2)-y^2(4x^2+12xy+9y^2)=9x^4+12x^3y-12xy^3-9y^4=9(x^2+y^2)(x^2-y^2)+12xy(x^2-y^2)=(x^2-y^2)(9x^2+12xy+9y^2)=(x+y)(x-y)(9x^2+12xy+9y^2)如果不懂,祝学习愉快!...