x-(2x-2分之x-1)+{3x-2分之3(x-2)}

问题描述:

x-(2x-2分之x-1)+{3x-2分之3(x-2)}

x-(2x-2分之x-1)+{3x-2分之3(x-2)}
=x-3/2x+1+3x-3/2x+3
=x+4