因式分解(x²-1)(x+3)(x+5)+12要过程
问题描述：
因式分解(x²-1)(x+3)(x+5)+12要过程
答
(x^2-1)(x+3)(x+5)+12 =(x+1)(x-1)(x+3)(x+5)+12 =[(x-1)(x+5)][(x+3)(x+1)]+12 =(x^2+4x-5)(x^2+4x+3)+12 =[(x^2+4x-1)-4][(x^2+4x-1)+4]+12 =(x^2+4x-1)^2-16+12 =(x^2+4x-1)^2-4 =(x^2+4x-1+2)(x^2+4x-1-2) =(x^2...