(-2)^2/m^2 +(根号3)^2/4=1 求m=?这道题怎么化简?

问题描述:

(-2)^2/m^2 +(根号3)^2/4=1 求m=?这道题怎么化简?

(-2)^2/m^2 +(根号3)^2/4=1
=>4/m^2+3/4=1
=>4/m^2=1/4
=>m^2=16
=>m=±4