说明方程X²-(2M+1)X+2M²+3=0 无实数根要过程啊!在线等!
问题描述:
说明方程X²-(2M+1)X+2M²+3=0 无实数根
要过程啊!在线等!
答
△=b²-4ac
= (2M+1)²-4*1*(2M²+3)
=4M²+4M+1-8M²-12
=-4M²+4M-12
=-(2M-1)²+1-12
=-(2M-1)²-11<0
所以方程X²-(2M+1)X+2M²+3=0 无实数根