氨的催化氧化反应4NH3+5O2=4NO+6H2O,在容积为5L的密闭容器中进行,0.5min后,NO的物质的量增加了0.3mol,则在0.5min内,此反应速率v(X )为（ C D ）A．v(O2)=0.01mol/(L•s) B．v(NO)=0.008mol/(L•s)C．v(H2O)=0.003mol/(L•s) D．v(NH3)=0.002mol/(L•s)

0.5min后,NO的物质的量增加了0.3mol 那么
NH3 = 0.3/4*4=0.3mol
O2 = 0.3/4*5=0.375mol
H2O = 0.3/4*6=0.45mol
t（时间）=0.5*60=30s
v(O2)=0.375/30/5=0.0025mol/(L•s)
v(NO)=0.3/30/5=0.002mol/(L•s)
v(H2O)=0.45/30/5=0.003mol/(L•s)
v(NH3)=0.3/30/5=0.002mol/(L•s)
所以是 CD