问几道数学有理数计算①(-6)×(-0.25)×11/14②-7×(-3)×(-0.5)+(-12)×(-2.6)
问题描述:
问几道数学有理数计算
①(-6)×(-0.25)×11/14
②-7×(-3)×(-0.5)+(-12)×(-2.6)
答
①(-6)×(-0.25)×11/14
=+(6×0.25)×11/14
=1.5×11/14
=33/28
②-7×(-3)×(-0.5)+(-12)×(-2.6)
=21×(-0.5)+(-12)×(-2.6)
=-10.5+(-12)×(-2.6)
=-10.5+31.2
=20.7
绝对正确
答
33/28
20.7
答
6×0.25×11/14
=3/2×11/14
=33/28 -7×3×0.5+12×2.6
=-10.5+31.2
=20.7
答
第一题28分之36第二题20.7