a^2b+b^2a+a+b+3ab+3 因式分解
问题描述：
a^2b+b^2a+a+b+3ab+3 因式分解
答
原式=a(ab)+b(ab)+a+b+3(ab+1)
=(a+b)(ab)+(a+b)+3(ab+1)
=(a+b)(ab+1)+3(ab+1)
=(ab+1)(a+b+3)
记得采纳哟亲
答
原式=(a^2b+b^2a+3ab)+(a+b+3)
=ab(a+b+3))+(a+b+3)
=(a+b+3)(ab+1)
答
ab(a+b)+a+b+3ab+3
(a+b)(ab+1)+3ab+3
(a+b)ab+1+3(ab+1)
(ab+1)(3+a+b)
答
a^2b+b^2a+a+b+3ab+3
=ab(a+b)+(a+b)+3(ab+1)
=（a+b）（ab+1）+3（ab+1)
=(a+b+3)(ab+1)
答
a^2b+b^2a+a+b+3ab+3
=ab(a+b)+(a+b)+3(ab+1)
=(a+b)(ab+1)+3(ab+1)
=(ab+1)(a+b+3)