fx=[xlnx+lnx+x+1]/x 求导,
问题描述:
fx=[xlnx+lnx+x+1]/x 求导,
答
fx=[xlnx+lnx+x+1]/x
=lnx +lnx/x +1+1/x
f'(x)=1/x +(1-lnx)/x² +0-1/x²
=1/x +(1-lnx)/x² -1/x²