因式分解 x²(x+y)²-x²y²=＿＿

问题描述：

答

=[x(x+y)+xy][x(x+y)-xy]
=x^2[x(x+2y)]
x^3(x+2y)

答

x²(x+y)²-x²y²
=[x(x+y)+xy][x(x+y)-xy]
=(x^2+xy+xy)(x^2+xy-xy)
=x^2(x^2+2xy)

答

原式=x^2((x+y)^2-y^2)
=x^2(x+y-y)(x+y+y)
=x^2(x+2y)x
=x^3(x+2y)

答

X的4次方+2X的三次方y+x的二次方y的二次方

答

x²(x+y)²-x²y²
=x²[（x+y)²-y²]
=x²(x+y-y)(x+y+y)
=x³(x+2y)
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答

x²(x+y)²-x²y²
=x²[(x+y)²-y²]
=x²(x+y+y)(x+y-y)
=x³(x+2y)