x³-x²-2x+2=0x²+y²-2x+4y+5=0|2x+1|>2
问题描述：
x³-x²-2x+2=0
x²+y²-2x+4y+5=0
|2x+1|>2
答
X2(X-1)-2(X-1)=0
（X2-2）（x-1)=0
x=正负根号2，x=1
2.
3. 2x+1>2或2x+1<-2
所以x>1/2 ,x<-3/2
答
1：x3-x2-2x+2=0
x2(x-1)-2(x-1)=0
(x2-2)(x-1)=0
x2=2或x=1
x=根号2或x=-根号2或x=1；
2:x2+y2-2x+4y+5=0
(x2-2x+1)+(y2+4y+4)=0
(x-1)2+(y+2)2=0
x-1=0,y+2=0
x=1,y=-2;
3：|2x+1|>2
2x+1>2或2x+1x>1/2或x
答
x³-x²-2x+2=0x²(x-1)-2(x-1)=0(x²-2)(x-1)=0x²-2=0或x-1=0x=±√2或x=1x²+y²-2x+4y+5=0(x-1)²+(y+2)²=0x-1=0y+2=0x=1y=-2|2x+1|>22x+1>2或2x+11/2或x